【LeetCode 217】存在重复元素

217. Contains Duplicate

题目难度: 简单

Given an array of integers, find if the array contains any duplicates.

Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

Example 1:

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**Input:** [1,2,3,1]
**Output:** true

Example 2:

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**Input:** [1,2,3,4]
**Output:** false

Example 3:

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**Input:** [1,1,1,3,3,4,3,2,4,2]
**Output:** true

解题思路

将list都放入set,利用set的特性解题

Solution

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class Solution:
   def containsDuplicate(self, nums):
       """
      :type nums: List[int]
      :rtype: bool
      """
       nums_set = set(nums)
       if len(nums_set) < len(nums):
           return True
       else:
           return False
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